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Vlada [557]
4 years ago
6

Determine whether quantities vary directly or inversely and find the constant of variation. If 5 bushels of wheat weigh 136 kg,

how much do 3.5 bushels of wheat weigh?
Mathematics
2 answers:
Contact [7]4 years ago
6 0
Well if 5 bushels = 136kg then 1 = 27.2 then 3.5 = 95.2 so it is directly and th vriation is 27.2

pentagon [3]4 years ago
4 0

Let the bushels of wheat is b and weight of the wheat is w.

We can say that more the bushels of wheat more will be the weight of the wheat.

Hence, the quantities  vary directly.

Therefore, we have

b=kw,  where k is the constant of variation.

Now, we have been given that 5 bushels of wheat weigh 136 kg. Thus, we have

5=136k\\
\\
k=\frac{5}{136}

Thus, the constant of variation is  \frac{5}{136}

Now, we have been given 3.5 bushels of wheat. Hence, we have

3.5=\frac{5}{136} w\\
\\
w=\frac{136\times 3.5}{5} \\
\\
w=95.2

Therefore, 3.5 bushels of wheat weigh 95.2 kg


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Answer:

1832.45

Step-by-step explanation:

2735 - 33% = 1832.45

8 0
3 years ago
When (81x^2/7) (2/9x^3/7) is simplified, it can be written in the form ax^b where a and b are real numbers. Find ab.
larisa86 [58]

Answer:

In improper form your solution will be \frac{90}{7}. As a mixed fraction it will be 12\frac{6}{7}.

Step-by-step explanation:

The first thing we want to do here is to simplify this expression. After doing so, " a " and " b " should be multiplied to result in a possible improper fraction,

\left(81x^{\frac{2}{7}}\right)\:\left(2/9x^{\frac{3}{7}}\right)\: - Apply exponential rule " \:a^b\cdot \:a^c=a^{b+c} "

= 81\cdot \frac{2}{9}x^{\frac{2}{7}+\frac{3}{7}} - Combine fractions \frac{2}{7} and \frac{3}{7}

= 81\cdot \frac{2}{9}x^{\frac{5}{7}} - Multiply the fractions, and simplify further

= \frac{162x^{\frac{5}{7}}}{9} = 18x^{\frac{5}{7}} - This is out simplified expression

Now that we have this simplified expression, we can see that a = 18, and b = \frac{5}{7}. Therefore, multiplying the two we should receive the improper fraction as follows,

18 * \frac{5}{7} = \frac{90}{7} - Note that this is in improper form. If you want your solution in a mixed fraction, it will be 12\frac{6}{7}.

5 0
4 years ago
Please help asap due at 8:00
natali 33 [55]

300 x 0.4 = 120

120 x 3 = 360

a. $360

300+360= 660

b. $660

2000 x 3.5 = 7000

7000 x 4 = 28000

a. $28,000

2000 + 28000 = 30000

b. $30,000

3 0
3 years ago
If sin2M = COS2N and m N= 30°, what is the measure of _M?<br> 150°<br> 90°<br> 60°<br> 30°
telo118 [61]

Answer:

below

Step-by-step explanation:

n = 30

cos 2*30 = cos 60 = 1/2

sin 30 = 1/2

2m = 30

m=15

8 0
3 years ago
A company is looking to fill its Board of Directors position. 3 positions will be for men, 2
ycow [4]

Answer:

1764 ways

Step-by-step explanation:

Given:

Men = 9

Women = 7

Required Men: 3

Required Women: 2

'

Required

Total Possible Outcome

The total possible outcome can be determine as follows;

Total = (Selection of Men) and (Selection of Women)

Calculating Selection of Men;

Let n represent total number of men; This implies that n = 9;

Let r represent number of men to select; This implies that r = 3;

The selection can be done in the following ways;

Male = nCr

Where nCr = \frac{n!}{r!(n-r)!}

Male = 9C3

Male = \frac{9!}{3!(9-3)!}

Male = \frac{9!}{3!(6)!}

Male = \frac{9 * 8 * 7 * 6!}{3!6!}

Male = \frac{9 * 8 * 7}{3!}

Male = \frac{9 * 8 * 7}{3*2*1}

Male = 84 ways

Calculating Selection of Women;

Let n represent total number of men; This implies that n = 7;

Let r represent number of men to select; This implies that r = 2;

The selection can be done in the following ways;

Female = nCr

Where nCr = \frac{n!}{r!(n-r)!}

Female = 7C2

Female = \frac{7!}{2!(7-2)!}}

Female = \frac{7!}{2!(5)!}

Female = \frac{7 * 6 * 5!}{2!5!}

Female = \frac{7 * 6}{2!}

Female = \frac{42}{2*1}

Female = 21 ways

Recall that

Total = (Selection of Men) and (Selection of Women)

Hence,

Total = 84 * 21

Total = 1764 ways

4 0
3 years ago
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