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Vlada [557]
3 years ago
6

Determine whether quantities vary directly or inversely and find the constant of variation. If 5 bushels of wheat weigh 136 kg,

how much do 3.5 bushels of wheat weigh?
Mathematics
2 answers:
Contact [7]3 years ago
6 0
Well if 5 bushels = 136kg then 1 = 27.2 then 3.5 = 95.2 so it is directly and th vriation is 27.2

pentagon [3]3 years ago
4 0

Let the bushels of wheat is b and weight of the wheat is w.

We can say that more the bushels of wheat more will be the weight of the wheat.

Hence, the quantities  vary directly.

Therefore, we have

b=kw,  where k is the constant of variation.

Now, we have been given that 5 bushels of wheat weigh 136 kg. Thus, we have

5=136k\\
\\
k=\frac{5}{136}

Thus, the constant of variation is  \frac{5}{136}

Now, we have been given 3.5 bushels of wheat. Hence, we have

3.5=\frac{5}{136} w\\
\\
w=\frac{136\times 3.5}{5} \\
\\
w=95.2

Therefore, 3.5 bushels of wheat weigh 95.2 kg


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Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

\angle EFG=\angle EFH+\angle HFG

18x+11=(5x+1)+(62)

18x+11=5x+63

Isolate variable terms.

18x-5x=63-11

13x=52

Divide both sides by 13.

x=\dfrac{52}{13}

x=4

The value of x is 4.

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\angle EFH=(20+1)^\circ

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The width of a rectangle field is 3h yards and its length is 3 yards longer than the width. The field has a fence around its per
d1i1m1o1n [39]

Answer:

Part a) P=(12h+2)\ yd

Part b) The expression that represent the cost of fencing the field is (336h+56)

Part c) \$1,736

Step-by-step explanation:

<u>The complete question in the attached figure</u>

Part a) we know that

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substitute the given values

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Part b) we know that

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