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notsponge [240]
3 years ago
13

Kimberly needs to solve the quadratic equation: x^2 + x – 2 = 2. which statement about how kimberly should solve this equation i

s true?
A.The quadratic formula is the only way to solve a quadratic equation.

B.The quadratic formula is a good method because this quadratic equation cannot be easily factored.

C.The quadratic formula is not a good method because you can factor the equation since -2 is divisible by 1.

D.Kimberly cannot solve this quadratic equation because it is not set equal to 0.
Mathematics
2 answers:
igor_vitrenko [27]3 years ago
4 0

B.The quadratic formula is a good method because this quadratic equation cannot be easily factored.

you just have to get 2 over to the left side of the equation.

Nitella [24]3 years ago
3 0

Answer:

THE ANSWER IS B

Step-by-step explanation:

TTM

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the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

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Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
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