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4 years ago

PLEASE HELP ASAP 2 QUESTION ON CONGRUENT TRIANGLES I WILL GIVE BRAINIEST

Mathematics

1 answer:

pantera1 [17]4 years ago

3 0

Answer:

See explanation

Step-by-step explanation:

Q11. Statement Reason

1. $\overrightarrow {MO}$ bisects $\angle PMN$ Given

2. $\angle PMO\cong \angle NMO$ Definition of angle bisector

3. $\overline{MO}\cong \overline{MO}$ Reflexive property

4. $\overrightarrow {OM}$ bisects $\angle PON$ Given

5. $\angle POM\cong \angle NOM$ Definition of angle bisector

6. $\triangle PMO\cong \triangle NMO$ ASA postulate

Q13.

1. Consider triangles ACB and DCE. In these triangles,

$\overline{BC}\cong \overline{EC}$ - given;
$\overline{AC}\cong \overline{DC}$ - given;
$\angle ACB\cong \angle DCE$ - as vertical angles (by vertical angles theorem)

Hence, triangles ACB and DCE are congruent by SAS postulate.

2. congruent triangles have congruent corresponding sides, so

$\overline{BA}\cong \overline{ED}$

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Will reward brainliest!

Lina20 [59]

Option D: Two irrational solutions

Explanation:

The equation is $17+3 x^{2}=6 x$

Subtracting 6x from both sides, we have,

$3x^{2} -6x+17=0$

Solving the equation using quadratic formula,

$x=\frac{6 \pm \sqrt{36-4(3)(17)}}{2(3)}$

Simplifying the expression, we get,

$\begin{aligned}x &=\frac{6 \pm \sqrt{36-204}}{6} \\&=\frac{6 \pm \sqrt{-168}}{6} \\&=\frac{6 \pm 2 i \sqrt{42}}{6}\end{aligned}$

Taking out the common terms and simplifying, we have,

$\begin{aligned}x &=\frac{2(3 \pm i \sqrt{42})}{6} \\&=\frac{(3 \pm i \sqrt{42})}{3}\end{aligned}$

Dividing by 3, we get,

$x=1+i \sqrt{\frac{14}{3}}, x=1-i \sqrt{\frac{14}{3}}$

Hence, the equation has two irrational solutions.

8 0

3 years ago

What’s the difference between an inscribed and circumscribed circle

kykrilka [37]

Inscribed is a polygon inside a circle with all points on a given point in the circle. Circumscribed is a circle inside a polygon with any given point touching just one point on the polygon. Hope this helped.

5 0

3 years ago

Read 2 more answers

200 days from March 3 is

lara31 [8.8K]

September 19 , 2018 is the answer

5 0

3 years ago

Read 2 more answers

zhuklara [117]

Step-by-step answer:

Given:

A triangle

Perimeter = 60 cm

longest side = 4* shortest side (x)

Solution:

longest side = 4x

shortest side = x

third (intermediate side = 60 -x -4x = 60-5x

The triangle inequality specifies that the sum of the two shorter sides must be greater than the longest side to form a triangle. Hence

x + y > 4x

x + 60-5x > 4x

60 - 4x > 4x

8x < 60

x < 60/8 = 7.5, or

x < 7.5

Therefore to form a triangle, x (shortest side) must be less than 7.5 cm.

Examine the options: both 7 and 5 are both less than 7.5 cm.

40, 30 and 25 all have a problem because the longest side (4 times longer) will exceed the perimeter of 60.

Now also examine cases where 4x is NOT the longest side, in which case we need

4x>=y

4x >= 60-5x

9x >=60

x >= 6.67

so x=5 will not qualify, because 4x will no longer be the longest side.

The only valid option is x=7 cm

The side lengths for x=7 and x=5 are, respectively,

(7, 25, 28)

5, 20, 35 (in which case, the longest side is no longer 4x=20, so eliminated)

7 0

3 years ago

What number must be added to 36 to obtain −12

dezoksy [38]

The correct answer is -48

36 + x = -12
X = -12 - 36
x = -48

36 + (-48) = -12
36 - 48 = -12

3 0

3 years ago