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Dima020 [189]
4 years ago
5

PLEASE HELP ASAP 2 QUESTION ON CONGRUENT TRIANGLES I WILL GIVE BRAINIEST

Mathematics
1 answer:
pantera1 [17]4 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

Q11.     Statement            Reason

1. \overrightarrow {MO} bisects \angle PMN     Given

2. \angle PMO\cong \angle NMO        Definition of angle bisector

3. \overline{MO}\cong \overline{MO}                   Reflexive property

4.  \overrightarrow {OM} bisects \angle PON    Given

5. \angle POM\cong \angle NOM        Definition of angle bisector

6. \triangle PMO\cong \triangle NMO       ASA postulate

Q13.

1. Consider triangles ACB and DCE. In these triangles,

  • \overline{BC}\cong \overline{EC} - given;
  • \overline{AC}\cong \overline{DC} - given;
  • \angle ACB\cong \angle DCE - as vertical angles (by vertical angles theorem)

Hence, triangles ACB and DCE are congruent by SAS postulate.

2. congruent triangles have congruent corresponding sides, so

\overline{BA}\cong \overline{ED}

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4 years ago
Two rectangles have the same area of 24cm².The second rectangle is 4cm shorter and 1cm wider than the first.What is the length a
lukranit [14]

Answer:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

Step-by-step explanation:

You can examine factor pairs of 24 to see which pairs meet the requirements:

  24 = 1×24 = 2×12 = 3×8 = 4×6

Factor pairs (2, 12) and (3, 8) have one factor that differs by 1 and another factor that differs by 4. We can use these numbers to describe the rectangles:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

5 0
3 years ago
Solve: 2x-3=6 I am stuck
Leni [432]
   
\displaystyle  \\  
2x - 3 = 6 \\  \\ 
2x = 6+3 \\  \\ 
2x = 9 \\  \\ 
x =  \boxed{\frac{9}{2}} = \boxed{4\frac{1}{2}} = \boxed{4,5}



6 0
3 years ago
Read 2 more answers
Triangle ABC is similar to Triangle XYZ. <br> Solve for x and y
Pie
Yz =5
Xz= 7
Hope this helps!!!
6 0
3 years ago
What is the value of X
klemol [59]

Answer:

x ≈ 23.31

Step-by-step explanation:

We can use the law of cosines because we know 2 sides and 1 angle.

The general formula  for the law of cosines if the triangle sides are a, b,c and α is the angle between sides a and b. c is the missing side.

c = \sqrt{a^{2} +b^{2} -2*a*b* cos \alpha }

In our problem the law of cosines is

x = \sqrt{21^{2} +13^{2} - 2*21*13 *cos 83}

x ≈ 23.31

5 0
3 years ago
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