Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
43
Step-by-step explanation:
Answer:
The blue one
4, 2
6, 3
12, 6
Step-by-step explanation:
Answer:
It will take 9 weeks
Step-by-step explanation:
56 + 8x
123
8x
67
x
8.375