$\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}$

3 0

3 years ago

Please help me :( !!<br> Will give brainliest <3

katovenus [111]

Answer:

2=173

4=309

7=513

9=649

Step-by-step explanation:

Since she starts with 37MB already download 37 will be a constant and for every second she is home she downloads 68 more MBs so to get the answers for the table you just have to do 37+ 68*(the number of seconds)

2=37+68(2)=173

4=37+68(4)=309

7=37+68(7)=513

9=37+68(9)=649

8 0

3 years ago

Express the following as a function of a single angle.<br> sin340cos120 - cos340sin120

Dima020 [189]

Hope this helps you.

8 0

3 years ago