Chebyshev’s Theorem establishes that at least 1 - 1/k² of the population lie among k standard deviations from the mean.
This means that for k = 2, 1 - 1/4 = 0.75. In other words, 75% of the total population would be the percentage of healthy adults with body temperatures that are within 2standard deviations of the mean.
The maximum value of that range would be simply μ + 2s, where μ is the mean and s the standard deviation. In the same way, the minimum value would be μ - 2s:
maximum = μ + 2s = 98.16˚F + 2*0.56˚F = 99.28˚F
minimum = μ - 2s = 98.16˚F - 2*0.56˚F = 97.04˚F
In summary, at least 75% of the amount of healthy adults have a body temperature within 2 standard deviations of 98.16˚F, that is to say, a body temperature between 97.04˚F and 99.28˚F.
Answer:
The answer is 64
Step-by-step explanation:
Since a square's sides are equal that means the dimensions are equal as well
8 x 8 = 64
14/22
well if you take the possibility and split it in half the you get your probability of it being
Well, things like sporting events, or freak storms are measured in days, or weeks. Depends. For weather, it could be hurricanes, tornado's, or even large fires(not quite weather, but could be)
