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Burka [1]
3 years ago
6

Im having trouble with this one P(2,-3), y= -6x+10

Mathematics
1 answer:
Otrada [13]3 years ago
4 0
Not a solution, when plugging in (2,-3) into y=-6x+10 you get -2, When y equals -3. They are not the same.
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8. Lisa types 6 pages in 36 minutes. Frank types 5 pages in 30 minutes. Do they type at the same rate? Use a proportion to expla
qaws [65]

Answer:

Yes

Step-by-step explanation:

Lisa and Frank type at the same rate.

They both type 1 page every six minutes.

Lisa types 6 pages every 36 minutes, and if we divide the minutes by the pages, we get

\frac{36}{6} = 6

And Frank types 5 pages ever 30 minutes, when we divide we get

\frac{30}{5} = 6

3 0
3 years ago
The population of a city this year [2018] is 34,500. The population is expected to grow by 2% each year. What will be the popula
Talja [164]
The answer would be A. 39,300.

I got this by multiplying 34,500 by 2% and getting 690. Since 2018 is 7 years away from 2025, I multiplied 690 by 7 getting 4,830. I added the 4,830 to the original population of 34,500 and got my answer, 39,300. Hope I helped!
8 0
4 years ago
James age is 3 years less than twice Tori's age the sum of their ages is 30 find their ages
blagie [28]
Error// Error// Error// Error// Error// Error//
7 0
3 years ago
Surface area of a box dimensions of 16 18 and 14
Arada [10]
16×14×2+16×18×2+14×18×2=1528
3 0
4 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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