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zalisa [80]
3 years ago
12

You can model an arch at your school using the equation y=−0.8(x−5)(x+5), where x and y are measured in feet. The x-axis represe

nts the ground. Find the width of the arch at ground level.
The width of the arch at ground level is ___ feet.
Mathematics
1 answer:
Masja [62]3 years ago
8 0

Answer:

10 ft

Step-by-step explanation:

At ground level, y = 0.  Setting −0.8(x−5)(x+5) = to 0, we get x = 5 and x = -5 as solutions.  The arch touchs the ground at x = -5 and x = 5 ft.

The width of the arch at ground level is 5 - (-5), or 10 ft.

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Answer:

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Answer:

Step-by-step explanation:

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2.

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8 0
4 years ago
Help!! Lots of points
murzikaleks [220]

\frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2}) }^{2}
Since they are both squared.

Evaluating 5^2 and 2^2 and finding the quotient also works.

\frac{ {5}^{2} }{ {2}^{2} } =  \frac{5 \times 5}{2 \times 2}   =  \frac{25}{4}  = 6.25\\  \frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2} )}^{2}  = 2.5 \times 2.5 = 6.25
The third option, "Evaluate 5^2 and 2^2 ...," and the last option, "Rewrite the expression as (5/2)^2 ...," are the correct choices.
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