Write the expressions as an equivalent power with a negative exponent. 1/49 and 27/125

1 answer:

7 0

$n^{-x}=\frac1{n^x}$

$\textcircled1\ \frac1{49}=\frac1{7^2}=\boxed{7^{-2}}$

$\textcircled2\ \frac{27}{125}=\frac{3^3}{5^3}=(\frac35)^3=\frac1{(\frac{5}{3})^3}=\boxed{\left(\frac53\right)^{-3}}$

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