The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked
miles.
<u>Solution:</u>
Given that,
- Julian walked 6/10 of a mile to his friends house
- Another 35/100 mile to the store
- He walked 1/4 of a mile back home
To find total distance walked by Julian we have to add the above stated values. That is, 
Factors of 10 = 
Factors of 100 = 
Factors of 4 = 
Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,


Which can also be written as
.
So, from the above calculation it can be said that Julian walked
.
1,725 yards, because 575×3=1,725. Or 575+575+575=1,725
Answer:
The function is missing in the question. The function is 
The answer is 4930
Step-by-step explanation:
Unit cost of a car is given as

Cost will be minimum when
x = -(-544)/ 2 x 0.8
= 340
Therefore, minimum cost for unit car is


= 4930