How do you find the HCF of 15t and 6s?
1 answer:
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Answer: Vertex : Maximum (2, 0)
Rules:
- (x + d)² = x² + 2dx + d² and (x - d)² = x² - 2dx + d²
- x² + 2dx = (x + d)² - d² and x² - 2dx = (x - d)² - d²
Solve:
x² - 4x + 4
x² - 2(2x) + 2²
(x - 2)²
Into vertex form: a(x - h)² + k
1(x - 2)² + 0
Identify:
vertex : (h, k) = (2, 0)
Find additional things, to graph the equation:
(i) x-intercept: (2, 0)
(ii) y-intercept: (0, 4)
Graph shown:
The horizontal distance between the base of the skyscraper to the ship is 1145 feet.
Data;
- Angle = 45 degree
- Observation deck (adjacent) = 1145 ft
- horizontal distance (opposite) = x
Using trigonometric ratios, we have the value of adjacent and angle, we can easily use tangent of the angle to find the horizontal distance
Substitute the values into the equation and solve
The horizontal distance between the base of the skyscraper to the ship is 1145 feet.
Learn more on trigonometric ratio here;