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VARVARA [1.3K]
3 years ago
11

Which multipilcation expression is to -6+(-6)+(-6)

Mathematics
2 answers:
slega [8]3 years ago
6 0

Answer:

-18

Step-by-step explanation:

Lelu [443]3 years ago
4 0

Answer:

-18

Step-by-step explanation:

We are beginning a sum by subtracting 6 and then repeating this twice.

That's equivalent to multiplying -6 by 3:     3(-6) = -18

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El piso de un habitación es de forma cuadrada. Tiene 10m de longitud por lado y debe ser cubierto con losetas cuadradas de 25cm
lora16 [44]

Answer:

4 fichas

Step-by-step explanation:

Paso 1

Encontramos el área de la habitación cuadrada.

Área de un cuadrado = longitud del lado²

Longitud lateral = 10 cm

Área del piso cuadrado = (10cm) ²

= 100 cm²

Paso 2

El suelo debe estar cubierto con baldosas cuadradas de 25 cm.

Por lo tanto: El número de mosaicos que serán necesarios =

Área del piso cuadrado ÷ Área de las baldosas

= 100cm² / 25 cuadrados

= 4 fichas

4 0
3 years ago
Solve for x in the equation x2 + 4x-4- 8.
Darina [25.2K]

Answer:

2(n+2x-6)

Step-by-step explanation:

n x 2+4x-4-8

8 0
3 years ago
The letter tiles shown below are in a bag. Whiteout looking I am going to draw one tile. What are my chances of drawing G?
Viktor [21]
# of G’s / # of total tiles = probability
8 0
3 years ago
Find the value of the combination. 7 C 2<br><br><br> a.21<br><br> b.42<br><br> c.49
USPshnik [31]
My guess would probably be A = 21
4 0
3 years ago
1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
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