Question

the perimeter of this rectangle and area, and if the area was 100 what would the value of x be, also if the area is 200, what is the value of x. thank you so much to whoever answers

Answer 1

Given:

Length of the rectangle = x + 21

Width of the rectangle = 5

To find:

Perimeter and area of the rectangle

Solution:

Perimeter = $2(l + w)$

                $=2(x+21+5)$

                $=2(x+26)$

Perimeter $=2x+52$ units

Area = length × width

        $=(x+21)\times 5$

Area $=5x + 105$ square units

Substitute perimeter is 100 and find the value of x:

$100=2x+52$

Subtract 52 from both sides.

$100-52=2x+52-52$

$48=2x$

Divide by 2 on both sides, we get

$24=x$

x = 24

Substitute area is 200 and find the value of x:

$200=5x + 105$

Subtract 105 from both sides.

$200-105=5x + 105-105$

$95=5x$

Divide by 5 on both sides, we get

$19=x$

x = 19

If the perimeter is 100, then the value of x is 24.

If the area is 200, then the value of x is 19.