the perimeter of this rectangle and area, and if the area was 100 what would the value of x be, also if the area is 200, what is
the value of x. thank you so much to whoever answers
1 answer:
Given:
Length of the rectangle = x + 21
Width of the rectangle = 5
To find:
Perimeter and area of the rectangle
Solution:
Perimeter =
Perimeter units
Area = length × width
Area square units
Substitute perimeter is 100 and find the value of x:
Subtract 52 from both sides.
Divide by 2 on both sides, we get
x = 24
Substitute area is 200 and find the value of x:
Subtract 105 from both sides.
Divide by 5 on both sides, we get
x = 19
If the perimeter is 100, then the value of x is 24.
If the area is 200, then the value of x is 19.
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So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same
a²+b²=c²
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