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Arlecino [84]
3 years ago
9

the perimeter of this rectangle and area, and if the area was 100 what would the value of x be, also if the area is 200, what is

the value of x. thank you so much to whoever answers

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Given:

Length of the rectangle = x + 21

Width of the rectangle = 5

To find:

Perimeter and area of the rectangle

Solution:

Perimeter = 2(l + w)

                =2(x+21+5)

                =2(x+26)

Perimeter =2x+52 units

Area = length × width

        =(x+21)\times 5

Area =5x + 105 square units

Substitute perimeter is 100 and find the value of x:

100=2x+52

Subtract 52 from both sides.

100-52=2x+52-52

48=2x

Divide by 2 on both sides, we get

24=x

x = 24

Substitute area is 200 and find the value of x:

200=5x + 105

Subtract 105 from both sides.

200-105=5x + 105-105

95=5x

Divide by 5 on both sides, we get

19=x

x = 19

If the perimeter is 100, then the value of x is 24.

If the area is 200, then the value of x is 19.

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