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3 years ago

15

Niah packed 24 dozen candles into 3 boxes. She packed an equal number of candles into each box. How many candles did Niah pack i

nto each box?

1 answer:

pshichka [43]3 years ago

8 0

8 because 24 candles going into 3 boxes is 24 divided by 3 which is 8

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Suppose that the credit remaining on a phone card (in dollars) is a linear function of the total calling time (in minutes). When

Virty [35]

Answer:

Credit remaining after 21 minutes = $30.4

Step-by-step explanation:

Credit remaining on a phone card is a linear function of the total calling time.

When graphed, let the linear function representing the line is,

y = mx + b

Where 'm' = slope of the line

b = y-intercept

From the graph,

Slope of the line = -0.12

y = -0.12x + b

If this line passes through a point (33, 28.96),

28.96 = -0.12(33) + b

b = 28.96 + 3.96

b = 32.92

Therefore, the linear function is,

f(x) = -0.12x + 32.92

where x = calling time

Credit left in the card after 21 minutes,

f(21) = -0.12(21) + 32.92

= -2.52 + 32.92

= $30.4

6 0

3 years ago

Find the area of the triangle.

BabaBlast [244]

Answer:

17.7 cm^2

Step-by-step explanation:

Use trig to find the height of the triangle. Then the area is bh/2.

Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.

Use triangle ABD to find the height, AD, of triangle ABC.

For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.

sin B = opp/hyp

sin 37 deg = AD/13.1

AD = 13.1 * sin 37 deg

AD = 7.9

AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.

area = bh/2

area = (4.5 cm)(7.9 cm)/2

area = 17.7 cm^2

5 0

3 years ago

a scout meeting lasts 2 hours. if 36 minutes was spent on making dream catchers, what percentage of the meeting is left

Llana [10]

Answer:

70% of the meeting is left.

Step-by-step explanation:

Hi, to answer this question, first, we have to convert the hours to minutes.

Since 1 hour = 60 minutes

For 2 hours:

1 /60 = 2/x

x = 2 (60)

x = 120 minutes

So, a scout meeting last 120 minutes (2 hours)

36 minutes already spent.

120-36 = 84 minutes left

So, if 120 is the 100% of the meeting, for 84 minutes:

120/100 = 84/x

1.2 =84/x

x = 84/1.2

x = 70%

70% of the meeting is left.

8 0

3 years ago

What is he value of F(-3)

PolarNik [594]

The correct answer is: " 10 " .

___________________________________________

→ " f(-3) = 10 " .

___________________________________________

Explanation:

___________________________________________

Given:

___________________________________________

f(x) = 7 − x ; if: x ≤ -3 ;

f(x) = x + 4 ; if: x > -3 ;

_________________________________________

Find: " f(-3) " :

_________________________________________

Note: " f(x) = f(-3) " ; → " x = - 3 " ;

Since " x = - =3 " ; → x is NOT greater than "-3" ;

→ So; " f(x) does NOT equal " x + 4" ;

_________________________________________

Consider our other option given:

We have "x = -3 " .

We our given: If " x ≤ -3 " ; {that is; if "x" is less than or equal to "-3" };

→ then: " f(x) = 7 − x " .

______________________________________________

Since: " x = - 3 " ;

→ then " x ≤ -3 " ; and:

→ f(x) = 7 − x ;

THEN:

→ f(-3) = 7 − (-3) ; → Note: Plug in "-3" for the value(s) of "x" in the equation;

and solve:

→ = 7 + 3 ;

= 10 .

___________________________________________________

→ f(-3) = 10 .

_____________________________________

The answer is: " 10 " .

_____________________________________

Hope this answer — and explanation — is helpful to you.

Best wishes in your academic pursuits!

_____________________________________

5 0

4 years ago

Does Cos (x+y)=cosx+cosy? Or not?

dangina [55]

$\bf \textit{Sum and Difference Identities}
\\ \quad \\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
\boxed{cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})}\impliedby notice
\\ \quad \\
cos({{ \alpha}} - {{ \beta}})= cos({{ \alpha}})cos({{ \beta}}) + sin({{ \alpha}})sin({{ \beta}})$

4 0

3 years ago