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Sidana [21]
3 years ago
8

$2/lb= cents/oz how to solve?

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0
16 oz in 1 lb
2$ divided by 16 is your answer
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I will give you a Brainliest
vladimir2022 [97]

if the circumference of the shield is 100.48inches, nits radius is 16 inches and the area of the front of the shield is about 803.84 square inches.

proof

circumference = 2x r x Pi implies r =circumference / 2Pi=100.48/2x3.14=16

area = Pi x r²=3.14 x 16²=804.84

8 0
3 years ago
The order pair below is a solution to which equation (24,6)
Illusion [34]
It would be much easier for me to help you pick the correct equation
if you would let me see the list of choices.

Since I can't see any of the choices, I'll just make up a few equations
that have the ordered pair  (24, 6)  as a solution:

         Y  =  0.25 x

         Y  =  x  -  18

         Y  =  0.5 x  -  6

         Y  =  0.1 x  +  3.6
7 0
3 years ago
Which of the following sets of ordered pairs represents a function?
allsm [11]
Answer:
A

Hope i helped :)
8 0
3 years ago
Susan, Deon, and Felipe sent a total of 160 text messages during the weekend. Felipe sent 4 times as many messages as Susan. Deo
Romashka [77]

Answer:

Susan sent 25 messages

Felipe sent 100 messages

Deon sent 35 messages

Step-by-step explanation:

160 = x + 4x + x + 10

160 = 6x + 10

6x = 150

x = 25

7 0
3 years ago
In the probability distribution to the​ right, the random variable X represents the number of marriages an individual aged 15 ye
kodGreya [7K]

The table of the probability is missing, so i have attached it.

Answer:

μ = 0.919

The interpretation of this is that;on the average, an individual aged 15 years or older has been involved in 0.919 marriages.

Step-by-step explanation:

The expected value which is also called mean value is denoted by the symbol μ. It is defined as the sum of the product of each possibility x with it's probability P(x) as the formula;

μ = Σx.P(x) = (0 × 0.272) + (1 × 0.575) + (2 × 0.121) + (3 × 0.027) + (4 × 0.004) + (5 × 0.001)

μ = 0.919

Thus, the interpretation of this is that;on the average, an individual aged 15 years or older has been involved in 0.919 marriages.

5 0
3 years ago
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