Answer:
a. 4r² b. 2r c. 6 cm
Step-by-step explanation:
The surface area A of the cube is A = 24r². We know that the surface area, A of a cube also equals A = 6L² where L is the length of its side.
Now, equating both expressions, 6L² = 24r²
dividing both sides by 6, we have
6L²/6 = 24r²/6
L² = 4r². Since the area of one face is L², the polynomial that determines the area of one face is A' = 4r².
b. Since L² = 4r² the rea of one face of the cube, taking square roots of both sides, we have
√L² = √4r²
L = 2r
So, the polynomial that represents the length of an edge of the cube is L = 2r
c. The length of an edge of the cube is L = 2r. When r = 3 cm.
L = 2r = 2 × 3 cm = 6 cm
So, the length of an edge of the cube is 6 cm.
I would check my math but 4/3 = 1.3 x 18= 24 divided by 2 for radius would be 12x12=144 x pie or 3.14 would be 452.16
We know that there are total 18 socks, and 3 blue pair
P(picking pairs of blue sock)=
3/18 or 1/6
As a result, the probability that he will pick a pair of blue socks is 1/6. Hope it help!
Changing the subject of an equation involves solving for another variable in the equation
The equation of t is 
<h3>How to change the subject of the equation</h3>
The equation is given as:
![N=\sqrt[2]{\frac{y_i-y_o}{t^2}}](https://tex.z-dn.net/?f=N%3D%5Csqrt%5B2%5D%7B%5Cfrac%7By_i-y_o%7D%7Bt%5E2%7D%7D)
Rewrite the equation as:
Evaluate the square root of t^2
Multiply both sides by t
Make t the subject, in the above equation
Hence, the equation of t is
Read more about subject of formula at:
brainly.com/question/657646
Answer:
t = 5/2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
3t + 7 = 2 + 5t
<u>Step 2: Solve for </u><u><em>t</em></u>
- [Subtraction Property of Equality] Isolate <em>t</em> terms: 7 = 2 + 2t
- [Subtraction Property of Equality] Isolate <em>t</em> term: 5 = 2t
- [Division Property of Equality] Isolate <em>t</em>: 5/2 = t
- Rewrite: t = 5/2
