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3 years ago

Help me on this math question

Mathematics

2 answers:

Maksim231197 [3]3 years ago

8 0

The answer is evaluate

Korolek [52]3 years ago

3 0

To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

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What is |-8| + |6| ?<br><br> GIVING 50 POINTS NEED HELP ASAP

stiks02 [169]

Answer:

Step-by-step explanation:

the absolute value of -8 is 8

the absolute value of 6 is 6.

6 + 8 = 14

give brainliest please!

hope this helps :)

4 0

1 year ago

Read 2 more answers

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

2 years ago

How do you do this problem?

Burka [1]

Let area of triangle AEC = x

Area of triangle BAC = 1/2 * 15 * 12 = 90

Area of triangle DCA = 1/2 * 15 * 6 = 45

90 = p + x and

45 = q + x Subtracting the 2 equations:-

90 - 45 = p - q

Answer p - q = 45

7 0

2 years ago

Read 2 more answers

Its length is

melamori03 [73]

Answer:

$100

Step-by-step explanation:

40x30=1200

1200/12=100

7 0

2 years ago

2. <br> Find the area of the region bounded by the graphs of y = -x2 + 3x + 4 and y = 4. (5 points)

Kipish [7]

Answer:

4.5 sq. units

Step-by-step explanation:

area = -⅓x³+3/2 x² ] 0 to 3

= -⅓(3)³+ 3/2 (3)² -0

= -9 + 27/2

= -9 + 13.5

= 4.5 sq. units

8 0

2 years ago