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4 years ago

Given: LPQN is a Rectangle, PM = QM Prove: LM = MN

Mathematics

1 answer:

melomori [17]4 years ago

6 0

Answer:

The Proof is given below.

Step-by-step explanation:

Given:

LPQN is a Rectangle

PM = QM

To Prove:

LM = MN

Proof:

In ΔLPM and Δ NQM

LP ≅ NQ ……{ Opposite sides of a Rectangle are congruent }

∠L ≅ ∠N =90° ……{ Measure of each vertex angle of rectangle are 90° }

PM ≅ QM ……{ Given }

ΔLPM ≅ ΔNQM …....{ By Hypotenuse Leg congruence test }

∴ LM ≅ MN ......{corresponding parts of congruent triangle }....Proved

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If A is the set of prime numbers and B is the set of

Natasha2012 [34]

The correct option is (A) None.

The numbers of digits that are common to both sets is none.

In mathematics, a set is a group of distinct objects that form a group. A set can contain any type of group of items, such as a grouping of numbers, days of the week, vehicle types, and so on.

Each element inside the set is referred to as a set element. When writing a set, curly brackets are used.
A simple instance of a set could be as follows. Set A = {1,2,3,4,5}. A set's elements can be represented in a variety of ways.
A roster form or even a set builder form is typically used to represent sets.

Now, according to the question;

Set A = {1,3,5,7,11,13,17,19,......} Prime Number Collection (The numbers which have only two factors i.e, 1 and the number itself)

Set B {15,25,35,45,55,......} Set of two-digit positive integers with the unit digit ("5").

Each two-digit positive integer with such a unit digit of 5 has much more than two factors; Set B has 1,5 as well as "itself" as factors.

As a result, these two sets are disjoint sets (no common element).

To know more about sets, here

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2 years ago

Can everyone give me there nicest greet

SOVA2 [1]

Answer:

Hi how are you doing?. Is that nice enough

Step-by-step explanation:

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4 years ago

A normal population has a mean of 19 and a standard deviation of 5.

dangina [55]

Answer:

a) $Z = 1.2$

b) 38.49% of the population is between 19 and 25.

c) 34.46% of the population is less than 17.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. If we need to find the probability that the measure is larger than X, it is 1 subtracted by this pvalue.

For this problem, we have that

A normal population has a mean of 19 and a standard deviation of 5, so $\mu = 19, \sigma = 5$ .

(a) Compute the z value associated with 25

This is Z when $X = 25$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 19}{5}$

$Z = 1.2$

(b) What proportion of the population is between 19 and 25?

This is the pvalue of Z when $X = 25$ subtracted by the pvalue of Z when $X = 19$ .

X = 25 has $Z = 1.2$ , that has a pvalue of 0.8849.

X = 19 has $Z = 0$ , that has a pvalue of 0.5000.

So 0.8849-0.500 = 0.3849 = 38.49% of the population is between 19 and 25.

(c) What proportion of the population is less than 17?

This is the pvalue of Z when $X = 17$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 19}{5}$

$Z = -0.40$

$Z = -0.40$ has a pvalue of 0.3446.

This means that 34.46% of the population is less than 17.

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3 years ago

How do you solve for x

ivann1987 [24]

Clear out any fractions by Multiplying every term by the bottom parts. Add or Subtract the same value from both sides. Divide every term by the same nonzero value. Combine Like Terms. Factoring. Expanding (the opposite of factoring) may also help.

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4 years ago

The quality of computer disks is measured by sending the disks through a certifier which counts the number of missing pulses. A

Westkost [7]

Answer:

Poisson distribution.

Step-by-step explanation:

We have the mean number of missing pulses per disk, which means that the distribution for X, the number of missing pulses, will be the Poisson distribution.

It is not the binomial distribution because we are not given the probability of a missing pulse on a disk, but the mean number of missing pulses.

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3 years ago