In simplest form it would be 0.35 then divide the numerator and denominator by the GCF u get 5.
Answer:
The right answer is:
"The one-day SAT prep class produces statistically significant improvements in SAT writing performance."
Step-by-step explanation:
The P-value gives us the probability of getting the sample results, given that the null hypopthesis is true. That is why, it the P-value is small enough (smaller than the level of significance) is an indicator that the null hypothesis may not be true.
In this case, the P-value (0.028) is smaller than the level of significance (0.05), so the null hypothesis is rejected and we can conclude that there is significant difference for the studentes that take the SAT prep-class.
The population only include the students that take teh SAT prep-class, so it is not useful to compare to the performance of students that didn't take the class.
The right answer is:
"The one-day SAT prep class produces statistically significant improvements in SAT writing performance."
Answer:
Step-by-step explanation:
here you go mate'
step 1
X / 2 + 1 > 3 equation
step 2
X / 2 + 1 > 3 simplify the equation
step 3
1/ 2 + 1 > 3 subtract the number at the front
1 / 2 + 1 (-1)> 3(-1)
step 4
1/2x>2 multiply
answer
x>4
Answer:
16/35
Step-by-step explanation:
Add up all of your marbles. 16 + 8 + 11 = 35. 16/35.
