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3 years ago

6

(08.01 MC)

1 answer:

Colt1911 [192]3 years ago

6 0

Part A:

We see that this pair of equations has 1 solution. On a graph, the solutions of 2 (or more) lines is where the lines intersect. In this case, since these lines intersect 1 time, they have 1 solution.

Part B:

As previously mentioned, the solutions of multiple lines is where the lines intersect. In this case, since they intersect at (4,4), that is the solution.

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Solve the system by graphing

Marta_Voda [28]

$\left\{\begin{array}{ccc}-2x=2y-4\\2x-y=-5\end{array}\right\\\\2y-4=-2x\ \ \ \ |+4\\2y=-2x+4\ \ \ \ |:2\\y=-x+2\\for\ x=0\to y=-0+2=2\to(0,\ 2)\\for\ x=2\to y=-2+2=0\to(2,\ 0)\\\\2x-y=-5\ \ \ \ |-2x\\-y=-2x-5\ \ \ \ |\cdot(-1)\\y=2x+5\\for\ x=0\to y=2(0)+5=5\to(0,\ 5)\\for\ x=-2\to y=2(-2)+5=1\to(-2,\ 1)\\\\Answer:\ (-1,\ 3)\to\ x=-1,\ y=3$

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3 years ago

Help for lots of points

Stells [14]

Answer:

45

Step-by-step explanation:

i hope this helps you :) i would do the middle one but you dont need that one

4 0

2 years ago

Read 2 more answers

Find the value of x, which makes the area of this triangle equal 72.

Ghella [55]

Area of a triangle=1/2(base x height)
Area=72, Base=8, Height=2x-3
Plug it in.
72=1/2(8 x (2x-3))
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3 years ago

Read 2 more answers

All of the following are equivalent EXCEPT x < 2 x - 2 < 4 2x < -4 x - 2 < -4

Vlad [161]

Answer:

solution

x<2,2x<-4,x-2<-4 are equvalent

but x-2<4 is not

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2 years ago

Please select the best answer from the choices provided

FromTheMoon [43]

Answer:

$\sqrt{122}$

Step-by-step explanation:

Given that,

Vector n = 4i-j

Vector m = 3i+3j

We need to find the value of m+2n.

Put all the values,

m+2n = (3i+3j)+2(4i-j)

= (3i+3j)+8i-2j

=11i+j

Magnitude of vector,

$|m+2n|=\sqrt{11^2+1^2} \\\\=\sqrt{121+1}\\\\=\sqrt{122}$

So the correct option is (c).

6 0

2 years ago