Answer:
The water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.
Step-by-step explanation:
Let 
, for 
. 
represents the temperature of the water, measured in degrees Celsius, and 
is the number of salmon swimming upstream to spawn, dimensionless.
We compute the first and second derivatives of the function:
(Eq. 1)
(Eq. 2)
Then we equalize (Eq. 1) to zero and solve for :
And all roots are found by Quadratic Formula:
, 
Only the first root is inside the given interval of the function. Hence, the correct answer is:
Now we evaluate the second derivative at given result. That is:
According to the Second Derivative Test, a negative value means that critical value leads to a maximum. In consequence, the water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.
It is usual to represent ratios in their simplest form so that we are not operating with large numbers. Reducing ratios to their simplest form is directly linked to equivalent fractions.
For example: On a farm there are 4 Bulls and 200 Cows. Write this as a ratio in its simplest form.
Bulls <span>: </span>Cows
4 <span>: </span>200
If we halve the number of bulls then we must halve the number of cows so that the relationship between the bulls and cows stays constant. This gives us:
Bulls <span>: </span>Cows
2 <span>: </span>100
Halving again gives us
1 <span>: </span>50
So the ratio of Bulls to Cows equals 1 : 50. The ratio is now represented in its simplest form.
An example where we have 3 quantities.
On the farm there are 24 ducks, 36 geese and 48 hens.
Ratio of ducks <span>: </span>geese <span>: </span>hens
24 <span>: </span>36 <span>: </span>48
Dividing each quantity by 12 gives us
2 <span>: </span>3 : 4
So the ratio of ducks to geese to hens equals 2 : 3 : 4 which is the simplest form since we can find no further common factor.
The answer is d because 4+8=12 and they are 4 units away from eachother:)
Answer: 50
Step-by-step explanation:
Step 1: 60% = .60
Step 2: 30 = .60Y
Step 3: Divide both sides of the equation by .30 to isolate the variable Y.
30/.60 = .60/.60Y
50=Y
Therefore, 30 is 60% of 50.
