Answer:
2 cows and 5 chickens.
Step-by-step explanation:
NOTE: This will be solved using simultaneous equations.
Let x = cows and y = chickens
1. form two equations
4x + 2y = 18 ... (1)
x + y = 7 .... (2)
2. make y (or x) the subject of one equation
x + y = 7
y = 7 - x ... (3)
3. Substitute (3) into (1)
4x + 2( 7 - x) = 18
4. solve for x
4x + 14 - 2x = 18
2x = 4
x = 2
5. Now substitute x value into equation (2)
x + y = 7
2 + y = 7
y = 5
∴ cows (x) = 2
chickens (y) = 5
Lemme just say this real quick, Ratio
A.) 1/2
B.) 3
For the first one, just plug the value of x (4) everywhere you see x in the formula.
For the second one, place 1 wherever you see f(x)
Hope this helps
Angles RZT, RZS, and TZS form triangle RZT, so they sum to 180. Thus, we have:
110+3s+8s=180
Simplifying, we have:
11s=70
Dividing by 11, we see that:
s=70/11
Therefore, RZS=3s=210/11, and TZS=8s=560/11.
