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Katen [24]
3 years ago
14

1. Solve for x. Show each step of the solution. 4.5(8 - X) + 36 = 102 - 2.5(3x+24) Answer:

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

x= -10

Step-by-step explanation:

       4.5(8 - x) + 36 = 102 - 2.5(3x + 24)

4.5(8) - 4.5(x) + 36 = 102 - 2.5(3x) -2.5(24)

       36 - 4.5x + 36 = 102 - 7.5x - 60

                72 - 4.5x = 102 - 7.5x - 60

                      -4.5x = 102 - 7.5x - 60 - 72

           -4.5x + 7.5x = -30

                           3x =  -30

                             x = -30/3

                             x = -10

Sorry if its wrong, I try my best.

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Five-sixths of Paco's stamps have pictures of animals.
goldenfox [79]

Answer:

20

Step-by-step explanation:

fraction of stamps that has animals on it x total number of stamps paco has = pictures with animals on it

(5/6) x 24 = 20

6 0
3 years ago
10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.
erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

p = \frac{4}{6} = 0.6667

10 normal six sided dice are thrown.

This means that n = 10

Find the probability of obtaining at least 8 failures.

This is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951

P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867

P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174

Then

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992

0.2992 = 29.92% probability of obtaining at least 8 failures.

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Answer:

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Step-by-step explanation:

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