Question

At the first track meet, Lonnie threw the shot put 51 1/3 feet. At the second track meet he threw the shot put 54 1/2 feet. Write an expression that would be used to find the distance he improved his throw from the first track meet to the second track meet and then solve expression. Be sure to show and explain your solution.

Answer 1

Answer:

Step-by-step explanation:

At the first track meet, distance of the shot put throw $D_{1}$ = $54\frac{1}{3}$

At the second track meet distance of the throw $D_{2}=54\frac{1}{2}$ feet

Expression that represents the improvement in the throw will be

D = $D_{2}-D_{1}$

D = $54\frac{1}{2}-51\frac{1}{3}$

D = $\frac{109}{2}-\frac{154}{3}$

D = $\frac{327-308}{6}$

D = $\frac{19}{6}$

D = $3\frac{1}{6}$ feet