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Alona [7]
4 years ago
14

I need assistance in this math problem Help Thx.

Mathematics
1 answer:
Cloud [144]4 years ago
8 0
(-2,3) I believe. I just learned this stuff in my last lesson lol
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34x=23+34/5+12x<br><br> btw anyone wanna add me on insta am bored
klasskru [66]

Answer:

sure its ablackmore

Step-by-step explanation:

7 0
3 years ago
Please help!!!! got to do this for math
Umnica [9.8K]

Answer:

11\sqrt{2}-5\sqrt{7}

7 0
3 years ago
Darren is painting a wooden block as part of his art project The block is a rectangular prism that is 12cm long by 9 cm wide by
Ksenya-84 [330]

Answer:

<h3>The surface area in square meters that Darren has to paint is 426cm^2</h3><h3>∴ A=426cm^2</h3>

Step-by-step explanation:

Given that Darren is painting a wooden block is a rectangular prism

Its length is 12 cm ,width is 9 cm and height is 5 cm

<h3>To find the surface area in square meters that Darren has to paint :</h3>

Let l be the length, w be the width and h be the height

Then l=12 cm , w=9 cm and h=5 cm

The formula for the Surface area is

A=2(lw+wh+hl) square units

Substitute the values in formula we get,

A=2(12(9)+9(5)+5(12))

=2(108+45+60)

=2(213)

=426

<h3>∴ A=426cm^2</h3><h3>∴ the surface area in square meters that Darren has to paint is 426cm^2</h3>

5 0
3 years ago
Find the least common multiple of 7,9 and 21
lawyer [7]
Free LCM Calculator determines the least common multiple (LCM) between 9 and 21 the smallest integer that is 63 that is divisible by both numbers. Least Common Multiple (LCM) of 9 and 21 is 63.
...
Prime Factorization of 21.
3 21
7 7
1
3 0
3 years ago
A spring has natural length 20 cm. Compare the work W1 done in stretching the spring from 20 cm to 30 cm with the work W2 done i
sashaice [31]

Answer:

W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)

W1 - W2 = 0

Step-by-step explanation:

Work done in stretching a spring is given by 1/2ke^2

Where, k is force constant and e is extension

e1 = 30cm - 20cm = 10cm

W1 = 1/2k(e1)^2 = 1/2×k×10^2 = 50k Joules

e2 = 40cm - 30cm = 10cm

W2 = 1/2k(e2)^2 = 1/2×k×10^2 = 50k Joules

W1 = W2 = 50k Joules provided W1 and W2 have equal force constant

Therefore, W1 - W2 = 0

7 0
3 years ago
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