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iris [78.8K]
3 years ago
10

Many airline companies have begun implementing fees for checked bags. Economic theory predicts that passengers will respond to t

he increase in the price of a checked bag by substituting carry-on bags for checked bags. As a result, the mean weight of a passenger's carry-on items is expected to increase after the implementation of the checked-bag fee.
Suppose that a particular airline's passengers had a mean weight for their carry-on items of 16 pounds, the FAA standard average weight, before the implementation of the checked-bag fee.

The airline conducts a hypothesis test to determine whether the current mean weight of its passengers' carry-on items is more than 16 pounds. It selects a random sample of 67 passengers and weighs their carry-on items. The sample mean is x = 17.1 pounds, and the sample standard deviation is
s = 6.0pounds. The airline uses a significance level of α =.05 to conduct its hypothesis test.

a. The hypothesis test is _____ test.

- The test statistic follows a _____ distribution. The value of the test statistic is_____.

b. Use the relevant statistical Distributions table to develop the critical value rejection rule.

According to the critical value approach, the rejection rule is:

A. Reject H0 if t ≤ − 1.997 or t ≥ 1.997
B. Reject H0 if z ≥ 1.645
C. Reject H0 if t ≥ 1.668
D. Reject H0 if t ≤ −1.668

c. The p-value is_____.

d. Using the critical value approach, the null hypothesis is _____, because _____ Using the p-value approach, the null hypothesis is_____, because_____ Therefore, you _____ conclude that the mean weight of the airline's passengers' carry-on items has increased after the implementation of the checked-bag fee.
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

Step-by-step explanation:

a. The hypothesis test is  one tailed_____ test.

(Because we check whether sample weight is greater than hence one tailed or right tailed)

The test statistic follows a __t___ distribution.(Because only sample std deviation s is known)

The value of the test statistic is___Mean difference/Std error =\frac{17.1-16}{\frac{6}{\sqrt{67} } } \\=1.58__

b. df = 66

Reject H0 if t ≥ 1.668

c. The p-value is_____0.059444

d. Using the critical value approach, the null hypothesis is _accepted____, because __t <1.668___ Using the p-value approach, the null hypothesis is__accepted___, because__p value <0.05 our significance level.___ Therefore, you __may___ conclude that the mean weight of the airline's passengers' carry-on items has increased after the implementation of the checked-bag fee.

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3 years ago
What is q + (-5)<br> _____. =3<br> 3.
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Please put down the steps?
e-lub [12.9K]
The answer is:  " x = 0, 1 " .
__________________________________________
Explanation:
__________________________________________
Given:
__________________________________________
   " √(x + 1)  <span>− 1 = x "  ;   Solve for "x" ;

First, let us assume that "x </span>≥ -1 "
<span>
Add "1" to EACH SIDE of the equation:

 </span>→  √(x + 1)  − 1  + 1 = x + 1  ; 

to get:  

 →  √(x + 1)  = x + 1 .

Now, "square" EACH side of the equation:

 →  [√(x + 1) ]²  = (x + 1 )² ;

to get: 

   x + 1 = (x + 1)² 

↔  (x + 1)²  = (x + 1) .


Expand the "left-hand side" of the equation:

 → (x + 1)² = (x + 1)(x +1) ;

Note: (a+b)(c+d) = ac +ad + bc + bd ;

As such:  (x + 1)(x + 1) = (x*x) + (x*1) +(1(x) + (1*1) ;
                                   =  x² + 1x + 1x + 1 ; 
                                   =  x²  + 2x  +  1 ;

Now, substitute this "expanded" value, and bring down the "right-hand side" of the equation; and rewrite the equation:
__________________________________________
   " (x + 1)² = (x + 1)(x +1) " ; 

  →  Rewrite as:  " x² + 2x + 1 = x + 1 " ;

 Subtract "x" ;  and subtract "1" ; from EACH SIDE of the equation:

               →   x² + 2x + 1 - x - 1 = x + 1 - x - 1 ; 

to get:    →   x² <span>− x = 0  

Factor out an "x" on the "left-hand side" of the equation:
___________________________________________
         </span>x² − x = x(x − 1) ;

         →  x (x − 1) = 0 ;

We have:  "x" and "(x − 1)" ; when either of these two multiplicands are equal to zero, then the "right-hand side of the equation equals "zero" .

So, one value of "x" is "0" .

The other value for "x" ;

→  x − 1 = 0 ;

Add "1" to each side of the equation:

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 " x = 0, 1 " .
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Step-by-step explanation:

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Answer:

Hey,

Let A be (-1,7)

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Once we plug x2=5 and x1=-1

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6 \sqrt{2}

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