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3 years ago

Add 3x2-4x+5, 9x - 10+2x2 and 7-5x2

Mathematics

2 answers:

mote1985 [20]3 years ago

6 0

Answer:

5x+2

Step-by-step explanation:

(3x2-4x+5)+(2x2+9x-10)+(-5x2+7)

Combine like-terms

The x-squared gets cancelled out

And you are left with 5x +2

Eva8 [605]3 years ago

4 0

I thinks this is the solution for this question. I tried doing it with explanations for you :) hope it helps

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Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .

All this to say that A is the point (1, 3), so

$2x+y=2+3=5$

5 0

4 years ago

What is the solution to the given inequality?

xenn [34]

Answer: x ≤3

Step-by-step explanation:

Your answer is correct

7 0

3 years ago

If b is the midpoint of AC, which of the following choices is the value of x?

katrin [286]

If B is the midpoint of AC, that means that the distances from A to B and B to C are the same. The distance from A to B is 8x + 4, and the distance from B to C is 10x - 6, so we can set these two equivalent:

8x + 4 = 10x - 6

Solving for x:

4 = 2x - 6 (subtract 8x from both sides)
10 = 2x (add 6 to both sides)
5 = x (divide both sides by 2)

So, x = 5, which is the second option given.

8 0

4 years ago

Find each value if f(x) = 2x - 1 and g(x) = 2 - x2.

bixtya [17]

Well i don’t know i just need me pints but sorry i’m so sorry

3 0

3 years ago

Explain why their are no solutions to the system of inequalities y ≤2x-5 y ≥2x+1

rosijanka [135]

Answer:

Sorry this is late and I think this is right.

They are both parallel, they have the same slope, and do not intersect. If you were to draw a slope out for it, you would find this to be true.

For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:

y < - 1/2x -3

y > 1/2x + 2

y= -x/2 -3 and y= -x/2 + 2 have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.

I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.

7 0

4 years ago