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2 years ago

Convert 9.8 cm to mm. (please show the steps to how you did the problem.)

Mathematics

2 answers:

UNO [17]2 years ago

4 0

Answer:

0.98

Step-by-step explanation:

$9.8 \div 10 \\ 0.98 \\ so \: answer \: is \: 0.98$

masha68 [24]2 years ago

4 0

Answer:

0.098

Step-by-step explanation:

1cm:100mm. 9.8cm-100 mm :0.098

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Answer:

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3 years ago

use coordinate notation to write the rule that maps each preimage to its image. The identify the transformation and confirm that

Ymorist [56]

The rigid transformations used for each figure:

Figure 5 - Reflection around x and y axes: (x, y) → (- x, - y)
Figure 6 - Horizontal and vertical translations: (x, y) → (x + 1, y - 2)

<h3>What transformation rules do create the resulting images?</h3>

In this question we must determine what kind of rigid transformations generates each image. Rigid transformations are transformations applied on geometric loci such that Euclidean distance is conserved. Now we proceed to determine the transformation rule for each case:

Figure 5 - Reflection around the x-axis followed by reflection around the y-axis.

(x, y) → (- x, - y)

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To learn more on transformation rules: brainly.com/question/9201867

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2 years ago

Triangles MOP and MNQ are similar. Find x. 2 3 4 5

Diano4ka-milaya [45]

Answer:

x = 3

Step-by-step explanation:

MQ : MN = 5:6

MP : MO = 5:6

MQ/MN = 5/6

Hence, MP/MO = 5/6

(5+x)/(6+(18/5)) = 5/6

5+x = (5/6)(48/5)

5+x = 8

x = 3

4 0

3 years ago

Jaya is the middle of three siblings whose ages are consecutive even integers. If the sum of their ages is 84,find Jaya’s age

Svetach [21]

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7 0

1 year ago

20 points!!!!!!!

castortr0y [4]

See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid

we know that
One edge of the cuboid has length 2 cm-----> I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1

[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]

100=2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0

using a graph tool------> to resolve the second order equation
see the attached figure

the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm

Find the length of a diagonal of the cuboid
diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm

the answer is
the length of a diagonal of the cuboid is 13.75 cm

4 0

3 years ago