Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
24 because when you plug in 0 for both x and y:
0=12(0)+24
12*0=0, leaving you with 24.
To find the final term to compete the square you need to divide the 'x' term by 2 then square it

- equivalent equation
Answer:
awww neither do i
Step-by-step explanation:
lol I got a 72 on my matb homework going to go jump off a cliff
Answer:
3(4+5)= 3(4)+3(5)
Step-by-step explanation: