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3 years ago

Which ordered pair is the best estimate for the solution of the system of equations? y=32x+6y=14x−2

Mathematics

1 answer:

Oduvanchick [21]3 years ago

4 0

Answer:

y=14 x=5

Step-by-step explanation:

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xxTIMURxx [149]

Answer:

A) $2.42, $2.33, $2.58

B) The best deal is 24 cupcakes for $56

Step-by-step explanation:

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3 years ago

TRUE OR FALSE: A translation maps each point to its image along a vector called the translation vector

Tomtit [17]

Answer:

True

Step-by-step explanation:

:) Hope this helps ! x

6 0

3 years ago

The senior class is taking a trip to the public library. They can travel in vans and buses. A van holds 8 people, and a bus hold

Lana71 [14]

Answer:

48=3b+v

Step-by-step explanation:

384=24b+8v

b standing for bus

v standing for vam

to simplify the equations you would divided by eight since all numbers are multiples

48=3b+v

8 0

3 years ago

For what value of x is PQ || BC?<br> A 5<br> B. 6<br> C. 7<br> D. 8

Dahasolnce [82]

Answer:

C. 7

Step-by-step explanation:

$In\: \triangle ABC\\\overline{PQ} \parallel \overline {BC}.. (given) \\$

Therefore, by Basic Proportionality theorem:

$\frac{AP}{PB} = \frac{AQ}{QC} \\\\\therefore \frac{x}{x+7} = \frac{x-3}{x+1} \\\\ \therefore \: \frac{x - x - 7}{x + 7} = \frac{x - 3 - x - 1}{x + 1} \\ (by \: dividendo) \\ \\ \frac{ - 7}{x + 7} = \frac{ - 4}{x + 1} \\ \\ \frac{7}{x + 7} = \frac{4}{x + 1} \\ \\ 7x + 7 = 4x + 28 \\ \\ 7x - 4x = 28 - 7 \\ \\ 3x = 21 \\ \\ x = \frac{21}{3} \\ \\ \huge \red{ \boxed{ x = 7}}$

5 0

3 years ago

8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member

tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

So the number of ways a committee of 5 students can be chosen from a student council of 30 students= $^{30}C_5=\dfrac{30!}{5!(30-5)!}$

$=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506$

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

4 0

3 years ago