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erastovalidia [21]
3 years ago
10

What are the values of a and b?

Mathematics
2 answers:
Gemiola [76]3 years ago
6 0

I hope this helps you

olasank [31]3 years ago
5 0

Step-by-step explanation:

By using cosine rules:

6/sin45° = b/sin90°

b = 6× sin45°/sin90°

b = 9.124(3d.p)

Also,

using Pythagoras theorm of right-triangle

b² = 6² + a²

9.124² = 6² + a²

83.247376 = 36 + a²

83.247376-36 = a²

47.247376 = a²

√47.247376 = a

6.874 = a

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Points S, L, and P on this grid represent the locations of the school, the library, and the park, respectively.
agasfer [191]

Using the distance formula, the distance from:

School to Library (SL) = 5 units.

Library to Park (LP) = 10 units.

<h3>What is the Distance Formula?</h3>

To calculate the distance between two points on a coordinate plane, the distance formula used is: d = \sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}.

Given the coordinates of each location as:

  • School, S = (0, 4)
  • Library, L = (4, 1)
  • Park, P = (-4, -5)

Distance from School to Library (SL):

SL = √[(4−0)² + (1−4)²]

SL = √[(4)² + (−3)²]

SL = √25

SL = 5 units

Distance from Library to Park (LP):

LP = √[(4−(−4))² + (1−(−5))²]

LP = √[(8)² + (6)²]

LP = √100

LP = 10 units

Learn more about the distance formula on:

brainly.com/question/661229

#SPJ1

7 0
1 year ago
The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
3 years ago
Find the area of the trapezoid. Leave your answer in simplest radical form. The figure is not
Irina18 [472]

Answer:

B.

Step-by-step explanation:

So you have to find the base of the trapezoid.

12 + 6 + 2 = 20

\frac{12+20}{2} *6=96cm^2

8 0
3 years ago
The picture frame has a perimeter of 100 inches. The width is 22 inches. Calculate the missing length. Use that answer to find t
ivanzaharov [21]

Answer:

39 inches.

858 inches²

Step-by-step explanation:

Length:- (if length = x)

2 ( 11 + x ) = 100

22 + 2x = 100

2x = 100 - 22

2x = 78

x = 78 ÷ 2

x = 39 inches

Area:-

Area = l × b

= 39 × 22

= 858 inches²

8 0
2 years ago
Tickets for a minor league baseball game for an adult and two children cost a total of $21 the adult ticket is three dollars mor
oksian1 [2.3K]

Answer:the cost of one child's ticket is $6

the cost of one adult ticket is $9

Step-by-step explanation:

Let x represent the cost of one child's ticket

Let y represent the cost of one adult ticket.

Tickets for a minor league baseball game for an adult and two children cost a total of $21. This means that

2x + y = 21 - - - - - - - - - - 1

The adult ticket is three dollars more than a child's ticket. This means that

y = x + 3

Substituting y = x + 3 into equation 1, it becomes

2x + x + 3 = 21

3x + 3 = 21

3x = 21 - 3 = 18

x = 18/3 = 6

y = x + 3 = 6 + 3

y = 9

6 0
3 years ago
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