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Katyanochek1 [597]
4 years ago
12

How does the order of operations relate to solving multi-step equations? Use examples of solving an equation, and then evaluatin

g it to help in your explanation.
Mathematics
1 answer:
givi [52]4 years ago
6 0
The order of operations helps keep answers for multi-step equations similar. If the proper order of operations are not followed, then answers may vary. To show an example:

4 / 2 - 1

The proper order of operations would be:

Divide first, before subtracting
4 / 2 - 1
2 - 1
1

But if subtracting was done before dividing:

4 / 2 - 1
4 / 1
4

So not following the proper order would yield different and erroneous answers.
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Maggie is practicing her penalty kicks for her upcoming soccer game. During the practice, she attempts 10 penalty kicks. If each
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Answer:

P(X \geq 8)= P(X=8) +P(X=9) +P(X=10)

And we can find the individual probabilities like this:

P(X=8)=(10C8)(0.65)^0 (1-0.65)^{10-8}=0.176  

P(X=9)=(10C9)(0.65)^1 (1-0.65)^{10-9}=0.072  

P(X=10)=(10C10)(0.65)^2 (1-0.65)^{10-10}=0.013  

And adding we got:

P(X \geq 8)= P(X=8) +P(X=9) +P(X=10)= 0.176+0.072+0.013=0.262

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.65)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Solution to the problem

For this case we want to find this probability:

P(X \geq 8)= P(X=8) +P(X=9) +P(X=10)

And we can find the individual probabilities like this:

P(X=8)=(10C8)(0.65)^0 (1-0.65)^{10-8}=0.176  

P(X=9)=(10C9)(0.65)^1 (1-0.65)^{10-9}=0.072  

P(X=10)=(10C10)(0.65)^2 (1-0.65)^{10-10}=0.013  

And adding we got:

P(X \geq 8)= P(X=8) +P(X=9) +P(X=10)= 0.176+0.072+0.013=0.262

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