D. There would be one less the second time because one would already be picked.
To get a percent rate, let the value of the car based on two consecutive years. The variable x represents a year. You can set any two numbers of year as long as they are consecutive; say x = 0 and x = 1.
Use the calculator to get instantly the values of V(x).
For V(x = 0)
V(x = 0) = 107,000(1.009)^[2/3(0)] = 107,000
For V(x = 1)
V(x - 1) = 107,000(1.009)^[2/3(1)] = 107,641
Another way of getting the percentage between two values is called the "relative change."
(107,641 - 107,000) / 107,000 = 0.0060 = 0.60%
Combine like terms by adding their FACES (Coefficients)
1) 4c² - 4
2) 20m^4 + 6m
3) -6a³ - 19a² + 8a - 10
4) -10a² - 2b + 3ab³ + 4a²b² -5b^4 - 9a²b² - 12a³b + 15ab³ = -10a² - 2b + 18ab³ - 5a²b² - 12a³b - 5b^4
5) 5a³ - 5a²
Answer:
C = (7, 6)
Step-by-step explanation:
The problem statement tells us the relation between the points is ...
(B-A)/(C-A) = 2/7
7(B -A) = 2(C -A) . . . . . . multiply by 7(C-A)
7B -7A +2A = 2C . . . . . add 2A
C = (7B -5A)/2 . . . . . . . divide by 2
C = (7(2, -4) -5(0, -8))/2 = (14, 12)/2 . . . . . fill in the values of A and B
C = (7, 6)
