Answer:
0.957mm
Explanation:
The on-axis magnetic field of a current loop(B_loop) is is 4.9 nT
B_loop = (2μAI) / (4πz^3).
Where z is defied as distance from the current carrying loop,
A is the total enclosed area of the loop,
I is the current,
μ is the permeability constant (4π*10^-7).
4.9 nT = (2* 4π*10^-7 *A *32A) / (4π* (50cm)^3)
4.9 *10^-9 = 5.12*10^-5 A
A = 0.0000957 m
=0.957mm
I thinks it’s A ...
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Are you asking what that is if so it would be called nuclear energy and if you want what is energy locked in the bonds of atoms that would be chemical energy
