Answer:
A
Explanation:
The thrifty gene hypothesis postulates that due to dietary scarcity during human evolution, people are prone to obesity by storing energy as fat, an ability to take advantage of rare periods of abundance and this is advantageous during times of food availability. individuals with greater adipose reserves would more likely survive famine. This tendency to store fat could lead to obesity.
FTO is an enzyme that is encoded in humans by FTO gene located on chromosome 16. Increase in this enzyme is associated with the regulation of energy intake but not feeding reward. Also, the set point theory indicates that bodies are meant to stay within a narrow weight range but it is susceptible to chnage overtime.
1. Organic compounds that contain carbon, hydrogen and oxygen and are the main source of energy for the body.
= CARBOHYDRATES
2. Inorganic substances found in foods needed for growth, regulation and development.
= MINERALS
3. Organic substances found in foods that aid enzymes. = VITAMINS
4. Fats, oils, and waxes that are insoluble in water. = LIPIDS
5. Organic compounds composed of amino acids that form the structure of the body.
= PROTEINS
6. Proteins that help drive the chemical reactions that occur in the body.
= ENZYMES
7. The conversion of the energy found in foods into a usable form of energy for the body.
= METABOLISM
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
