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Lera25 [3.4K]
3 years ago
5

Lou's employer covers 70% of the cost of a $3800-per-year health insurance plan and 90% of the cost of a $1200per-year disabilit

y insurance plan. If Lou gets paid monthly,what is the total amount deducted from his gross income for health and disability insurance during each pay period?
Mathematics
2 answers:
saul85 [17]3 years ago
8 0

Answer:

$105.00

Step-by-step explanation:

APEX

gizmo_the_mogwai [7]3 years ago
7 0
To answer this question correctly, first we must find out how much lou pays for health and disability insurance for a year total, then divide that number by 12, for each month of the year to find out how much he pays monthly. The calculation and answer would be the following: ((Health insurance cost * 30%) + (Disability cost * 10%)) / 12 = (1140+120)/12 = $105 monthly
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Please somebody help with my math please pick one section to do ​
IRINA_888 [86]

Answer:

Number 1.

Step-by-step explanation:

Largest 4: 4m

2nd Largest: 4m

4 0
3 years ago
“The line that passes through point H has the equation y=-2x -3”
Katena32 [7]

Answer:

Step-by-step explanation:

Generally

The equation of a line is given as

y = mx + c

Where

m is the slope

c is the intercept on y axis

Note: if two lines are parallel, their slopes are equal

I.e M1 = M2 =m

If two lines are perpendicular, then, their slopes are given as

M2 = - 1/M1

Given that,

The line that pass through the point H has an equation

y = -2x-3

From equation of a line, we know that, the slope of the line that passes through H is -2

m = -2

We want to find the equation of a line parallel to line that passes through H

If the line we want to find is parallel to the given line, then, their slope are equal,

So, the slope of line that passes through point G is m=-2

So, the equation of the line that passes through point G is

y = mx + c, m=-2

y = -2x + c

So, we need to find c, so, using the point G it passes through,

G = (2,1) I.e x = 2 and y = 1

y = -2x + c.

1 = -2(2) + c

1 = -4 + c

1+4 = c

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3 0
3 years ago
4^x+7 = 8^2x-3 Solve each equation showing work please
RUDIKE [14]

If 4=2^2

8=2^3

(2^)2x+10=(2^)6x

(2^)6x-(2^)2x=10

(2^)2x×7=10, where x has no real value

3 0
3 years ago
What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint
leonid [27]

The right answer is c. –2.24, 2, 2.24


This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.


1. Using a graphing calculator.


We have the following polynomial equation:

x^3-5x+5=2x^2-5


By ordering this equation we have:

x^3-2x^2-5x+10=0


So, we can say that this equation comes from a function given by:

f(x)=x^3-2x^2-5x+10


Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of f(x) which are:


x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236


Finally, rounding noninteger roots to the nearest hundredth we have:


\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}


2. Using a system of equations.


The ordered equation is:

x^3-2x^2-5x+10=0


By arranging to factor out we have:

x^3-5x-2x^2+10=0


Then, by factoring:

x(x^2-5)-2(x^2-5)=0


Term (x^2-5) is a common factor, thus:


(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}

6 0
3 years ago
Read 2 more answers
What two numbers multiplied gives you 175
Pavlova-9 [17]
35x5=175
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8 0
3 years ago
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