3/4= j-1/2
first to add 1/2 to both sides to solve for j
3/4 + 1/2= j
second you find a common denominator in order to add 3/4 and 1/2, the common denominator would be 4, you would have to change 3/4 at all because the denominator is already 4 but in order to make the denominator of 1/2, 4 you would have to multiply both the denominator and numerator by 2 so
3/4 + 2/4 = 5/4
so 5/4 =j
to check your answer you plug 5/4 in for j
3/4 = 5/4 -1/2
again you need to find a common denominator between 5/4 and 1/2 which again would be 4, and again you wouldn't change 5/4 but you would multiply both the numerator and the denominator of 1/2 so
3/4= 5/4-2/4
5-2= 3 and you would keep the 4 so
5/4 - 2/4 = 3/4
so j = 5/4
Not 100% positive, but I think that it’s
13
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I hope this helps
Answer:
the number of adult ticket sold is 107 tickets
Step-by-step explanation:
The computation of the number of adult ticket sold is shown below:
Let us assume the number of tickets be x,
So, the adult be x
And for student it would be 3x
Students= 2x
Adults= x
Total = 4x
Now the equation could be
4x = 428
x = 107
This x signifies the adult tickets sold i.e 107
Hence, the number of adult ticket sold is 107 tickets
1) The graph consists of three horizontal segments, with discontinuities (jumps) at x = 1, x = 2, and x = 3.
A horizontal segment at y = - 2 for the values x = 0 to 1.
A horizontal segment at y = - 1 for values x = 1 to 2
A horizontal segment at y = 0 for values x - 2 to 3.
2) To know whether the end points of a segment are defined by the left or the right values you have to look for the circle at the extreme of the segment: if it is a solid dot, means that the end is included, if is is an open circle (white inside) then the end is not included in that segment.
3) That function is based on the function named integer part because if relates y with the integer part of x.
The integer value function is [x] and it makes correspond y values witht he integer values of x.:
y = 0 witht the integer value of x for x between 0 and 1, excluding 1.
y = 1 with the integer value of x between 1 and 2 (excluding 2)
y = 2 with the integer value of x between 2 and 3 (excluding 3)
y = 3 with the integer value of x between 3 and 4 (excluding 4)
But our function is two units below, so it is [x] - 2