The little lines on each side of the rhombus mean that all the sides are the same length.

We can set line LM and MN equal to solve for X, then we can solve the length of a side.

3x-3 = x+7

Add 3 to each side:
3x = x +10

Subtract x from each side:

2x = 10

Divide both sides by 2:
x = 10/2
x = 5

Now we have the value for x, replace x in one of the side formulas:

x +7 = 5+7 = 12

Each side = 12 units.

The perimeter would be 12 + 12 + 12 + 12 = 48 units.

3 0

3 years ago

Read 2 more answers

The question is below

anastassius [24]

Answer:

uh there is no question below

Step-by-step explanation:

8 0

2 years ago

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Expressed as a product of its prime factors in index form, a number N is

Elena-2011 [213]

<u>ANSWER</u>

$5N^2=3^{2} \times 5^{5} \times x^{6}$

<u>EXPLANATION</u>

$N=3\times5^2 \times x^3$ .

$5N^2=5(3\times5^2 \times x^3)^2$

Recall this property of exponents;

$(a^m)^2=a^{m} \times a^m$

So our product becomes;

$5N^2=5(3\times5^2 \times x^3) \times (3\times5^2 \times x^3)$

$5N^2=5\times 3\times 3 \times 5^2 \times 5^2 \times x^3 \times x^3$

$5N^2=3\times 3\times 5 \times 5^2 \times 5^2 \times x^3 \times x^3$

Recall this law of exponents:

$a^m \times a^n =a ^{m+n}$

$5N^2=3^{1+1} \times 5^{1+2+2} \times x^{3+3}$

$5N^2=3^{2} \times 5^{5} \times x^{6}$

7 0

3 years ago

Suppose a population has a doubling time of 25 years. By what factor will it grow in 25 years? 50 years? In 100 years?

rewona [7]

Answer:

2,4, and 8.

Step-by-step explanation:

If the population has a doubling time of 25 years, that means that in 25 years the population will double. So for 25 years, the factor will be 2. For 50 years, the factor would be 2x2, which is 4. For 100 years, it is 4x2 which is a scale factor of 8.

4 0

3 years ago