Answer:
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the explanation is in the picture
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Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
28.27530
Step-by-step explanation:
Given the expression 62.834 × 0.45, to solve this expression, first we need to convert it to fraction
62.834 = 62834/1000
0.45 = 45/100
Take the product if the resulting fraction:
62.834 × 0.45 = 62834/1000 × 45/100
= (62834×45)/1000×100
= 2,827,530/100,000
= 28.27530
The unit rate is 2/3 because in the line y=2/3x, 2/3 is the slope (y=mx+b). The slope of the line is pretty much the definition of a unit rate because the unit rate is a constant addition or subtraction over and over. In addition, it is a straight line(y=mx+b) and the values are going up at a constant rate of 2/3.
Answer:
A. X-coordinate
Step-by-step explanation:
I calculated it logically
