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2 years ago

14

The Malden family rented a car for $25.00 per day ,plus .25 cents per mile write an expression that represents the total cost of

their car rental

2 answers:

Nikolay [14]2 years ago

4 0

total cost = .25m + 25d

M is the number of miles driven and D is the number of days the car was rented

dezoksy [38]2 years ago

3 0

Answer:

C=0.25m+25.00

Step-by-step explanation:Total cost is .25 per mile times the # of miles + the $25 daily fee

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A=pir^2 solve for pi

VashaNatasha [74]

Given problem;

A = $\pi$ r²

Solve for π;

To solve for π implies that we make it the subject of the expression.

So;

A = π r²

Now multiply both sides by $\frac{1}{r^{2} }$

So;

A x $\frac{1}{r^{2} }$ = $\pi$ x r² x $\frac{1}{r^{2} }$

r² cancels out from the right side and leaves only π;

π = $\frac{A}{r^{2} }$

So $\pi = \frac{A}{r^{2} }$

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2 years ago

Sam is selling homemade cookies to raise money for charity. Each cookie sells for $.50. Sam spent $90 on baking supplies and eac

Hunter-Best [27]

9514 1404 393

Answer:

360

Step-by-step explanation:

Sam obtains a "contribution margin" of $0.50 -0.25 = $0.25 per cookie. That will cover the cost of baking supplies when he sells ...

$90 / ($0.25/cookie) = 360 cookies

Sam needs to sell 360 cookies before he can start making a profit.

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If you like, you can find Sam's break-even point by equating revenue and cost. The is the number of cookies Sam must sell for a profit of 0, that is, for non-negative profit.

P = R - C

0 = R - C

R = C

0.50n = 90 +0.25n

0.25n = 90 . . . . subtract 0.25n

n = 90/0.25 = 360 . . . .divide by the coefficient of n

You may notice this is similar to our description above.

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2 years ago

Write a equation of a hyperbola given the foci and the asymptotes

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The standard equation of a hyperbola is expressed as

$\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}$

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}$

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$y=\pm\frac{a}{b}(x-h)+k$

Given that the asymptotes are

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