What is the classification for this polynomial? u^2 v^3 w

Mathematics

1 answer:

andrew11 [14]1 year ago

5 0

Answer:

A...

Step-by-step explanation:

Not completely sure. :<

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GrogVix [38]

Answer:

Rains and Splash

Step-by-step explanation:

2 verbs rains and splash

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2 years ago

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Im not sure how to solve this please help

Effectus [21]

Look at the corresponding angle to 82, which is to the left of line b

It also measures 82 according to "corresponding angle theorem"

Then
angle x is equal to it as they are vertical pair of angle

so that, the measure of x equals 82 degree

I hope that helps

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2 years ago

Find the surface area of each figure. Round your answer to the nearest tenth if necessary.

dedylja [7]

Answer:

556

Step-by-step explanation:

Surface area of the cuboid=2*(lb+bh+lh)

Surface area=2*(110+80+88)=556

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2 years ago

What is the scale factor?

Fed [463]

Answer:

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it literally doubles in size

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2 years ago

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If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

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2 years ago