Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Substitute all x in the equation to 1.6
∴6-4(1.6)=-1.6/4
∴-0.4=-0.4
∴Yes
<h3>
Answer: Choice E</h3>
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Explanation:
Think of 25 as 25/1 and 5 as 5/1
Choice E is really saying 
which becomes 
. Note the second fraction flips and we change to a multiplication sign.
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Or you could think of it like this:
to help see why the answer is E.
Answer:
7/3
Step-by-step explanation:
i hope this works :)
