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svp [43]
2 years ago
14

An above-ground swimming pool in the shape of a cylinder has a diameter of 18 feet and a height of 4.5 feet.If the pool is fille

d with water to 6 inches from the top of the pool, what is the volume to the nearest cubic foot or their water in the pool
Mathematics
1 answer:
steposvetlana [31]2 years ago
5 0

Answer:

The volume of the water in the pool is 1,017 cubic feet

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

we have

r=18/2=9\ ft ----> the radius is half the diameter

Remember that

1\ ft=12\ in

so

6\ in=6/12=0.5\ ft

To find out the height of the water, subtract 0.5 feet from the height of the swimming pool

h=4.5-0.5=4\ ft

assume

\pi =3.14

Find the volume of the water

V=(3.14)(9^{2})(4)

V=1,017\ ft^3

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A recent college graduate is planning to take the first three actuarial examinations in the coming summer. She will take the fir
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Answer:

(a) 0.7

(b) \frac 13

Step-by-step explanation:

Let E_1, E_2, and E_3 be the events of passing the 1st, 2nd, and 3rd exam individually.

Given that P(E_1)=0.9\;\cdots(i)

where P(E_1) denotes the probability of passing the 1st exam.

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P\left(\frac{E_2}{P(E_2/E_1)}\right)=0.7\;\cdots(iii)

(a) For passing all the exams, the condition is, at first, she has to pass the 1st and 2nd exam, then she has to pass the 3rd exam too. The probability for this conditional has been given as 0.7.

So, the probability that she passes all three exams is 0.7.

(b) Given that she didn't pass all three exams that means she either failed in 1st exam or she passed the 1st and failed in 2nd exam or she passed both 1st and 2nd but failed in the 3rd exam.

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\Rightarrow P(F)=(1-0.9)+(1-0.8)+(1-0.7)=0.6

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P(F_2)=1-\frac{P(E_2)}{P(E_1)}

\Rightarrow P(F_2)=1-0.8=0.2

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P\left(\frac{F_2}{F}\right)=\frac{P(F_2)}{P(F)}

\Rightarrow P\left(\frc{F_2}{F}\right)=\frac{0.2}{0.6}=\frac{1}{3}=0.33

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Basically anything greater than zero...k>0

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