1) The measures of the opposite angles of an inscribed quadrilateral are supplementary, add up to 180.
That means that angle ROP and angle RQP are supplementary.
We can add them and set them equal to 180 so that we can solve for x first.
∠ROP + RQP = 180
x + 17 + 6x - 5 = 180
7x + 12 = 180
7x = 168
x = 24
Now use the 24 for x and solve for the measure of angle ROP.
∠ROP = x + 17
∠ROP = 24 + 17
∠ROP = 41
The answer is A
2) The answer is A.
Hope this helps :)
Step-by-step explanation:
Use triangle congruency:
BC=EC, AC=DC - Given
m∠DCE = m∠ACB because they are vertical angles
Therefore ΔABC ≅ ΔDEC because of Side-Angle-Side congruency
AB=DE because corresponding parts of congruent triangles are also congruent (CPCTC)
Answer:
Step-by-step explanation:
2a. f(-3) = (-3)^2-4(-3)+6 = 9+12+6 = 27
2b. f(-2) = 3(-2)^2-(-2)^3 -2 +1 = 3(4) - (-8) -2 +1
= 12+8-1 = 19
Step-by-step explanation:
Given equations:
y = x² + 3x - 29 ------ (i)
y = 2x - 9 ---------------- (ii)
Now to solve this problem, we must determine the value of x and y;
Equate equations 1 and 2;
x² + 3x - 29 = 2x - 9
x² + 3x - 2x - 29 + 9 = 0
x² + x - 20 = 0
x² + 5x - 4x - 20 = 0
x(x + 5 ) - 4(x + 5) = 0
(x - 4) (x+ 5) = 0
x - 4 = 0 or x + 5 = 0
x = 4 or x = -5;
So; solve for y now;
y = 2x - 9
input x = 4 or x = -5;
y = 2(4) - 9 or y = 2(-5) - 9
y = -1 or y = -19
above, -6 and -<span>1 2x2</span> - 6x - 1x - 3. Step-4 :
