<h2>
Answer with explanation:</h2>
Given : The proportion of New Zealanders consume five or more servings of soft drinks per week :
a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006
b) Confidence interval for population proportion (p) :

, where
= Sample proportion.
n= Sample size.
z* = Critical value.
For n= 2006 ,
and critical value for 95% confidence interval : z* = 1.96
Then , the required confidence interval will be :






i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = 
c) 
176\times100\%)[/tex]
d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.
Find 5.25% of 200
remember
1% of 100=1
therefor
1% of 200=2
just remove the decimal and double it (for this special case of finding percent of 200)
5.25% of 200=5.25 times 2=10.5
answer is 10.5 pounds of copper
(the legit way is 0.0525 times 200=10.5 pound)
10.5lb is answer
Answer:
Sterling made the correct statement.
Step-by-step explanation:
Feel free to give brainliest.
Have an outstanding day!
Answer:

Step-by-step explanation:
first multiply both side by 2 to get rid of the fraction




