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antiseptic1488 [7]
3 years ago
10

Find the values for x and y

Mathematics
2 answers:
mel-nik [20]3 years ago
4 0
Both form straight angles, which are 180 degrees.

x+4y+x+y=180
2x+5y=180

4x+y=180

Solve the second equation for y and substitute the variable.
y= -4x+180

2x+5(-4x+180)=180
2x-20x+900=180
-18x= -720
x=40

Plug the x value in
4(40)+y= 180
160+y=180
y=20

Final answer: x=40, y=20
Assoli18 [71]3 years ago
3 0
X+4y+x+y= 4x+y=180
simplify by adding like terms
2x+5y= 4x+y=180
Subtract y from each side
2x+4y=4x=180
Subtract 2x from each side
4y=2x=180
y=180/4=45
x=180/2=90
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3 years ago
If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?
Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor  (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2

where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

5 0
3 years ago
On monday 2/3 of the team practiced, Tuesday 7/8, wendsday 1/2 and Thursday 3/4 which is the most
dimulka [17.4K]
 i believe its tuesday 7/8


6 0
3 years ago
Read 2 more answers
See image for question.​
kotegsom [21]

Answer:

<h3>#7</h3>

(a)

<u>Sample space:</u>

  • 1*1, 1*2, 1*3, 1*4,
  • 2*1, 2*2, 2*3, 2*4,
  • 3*1, 3*2, 3*3, 3*4,
  • 4*1, 4*2, 4*3, 4*4

Total 16 outcomes

(b)

  • (i) P(even) = 12/16 = 3/4
  • (ii) P(3x) = 7/16
  • (iii) P(perfect square) = 4/16 = 1/4
<h3>#8</h3>

(a) <u>Sample space:</u>

  • 1T, 1H, 2T, 2H, 3T, 3H, 4T, 4H

Total 8 outcomes

(b)

(i) 1T, 3T

  • P(T and odd) = 2/8 = 1/4

(ii) 1H, 4H

  • P(H and square) = 2/8 = 1/4

(iii) 1H, 2H, 3H, 4H

  • P(H) = 4/8 = 1/2

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3 years ago
Assume that a​ student's alarm clock has a 11.2 ​% daily failure rate. What is the probability that the​ student's alarm clock w
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