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Hoochie [10]
3 years ago
6

find the shadow cast by a 10 foot lamp post when the angle of elevation of the sun is 58 degrees. find the length to the nearest

tenth of a foot.

Mathematics
1 answer:
ddd [48]3 years ago
3 0
If you looks at the well drawn picture that I drew, you'll notice that we notice that we can use the trigonometric ratio tan; in this case:

tan58=\frac{10}{x}
Solving this, we get:
x=\frac{10}{tan58}
Which gets us that x=6.25 (approximately)

(It really wasn't that great of a picture but still :D)

:)

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What is the value of the expression x^2y–y+xy^2–x for x=4 and y=0.25?
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0 (zero)

Step-by-step explanation:

{x}^{2} y - y + x {y}^{2}  - x  \\  =  {4}^{2} \times  0.25 - 0.25 + 4 \times  {0.25}^{2}  - 4 \\  = 16 \times  0.25 - 0.25 + 4 \times  0.0625- 4  \\  = 4 - 0.25 + 0.25 - 4 \\  = 0 \\  \\  \purple {\boxed{ \bold{ \therefore \:  {x}^{2} y - y + x {y}^{2}  - x  = 0}}}

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Murrr4er [49]

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Step-by-step explanation:

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Plz help answer these!!! WILL MARK AS BRAINLIEST!!!
Aleksandr [31]

b: 4 x (2 x 9) = 72

c: 7 x (2 x 3) = 42

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7 0
3 years ago
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In the given diagram abc is a right angle with DG CB segment AB is divided into four equal parts . The coordinates of point F ar
pickupchik [31]

Answer:

E(3.75,-2.5)

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Step-by-step explanation:

Point E is the midpoint of the segment AB, then it has coordinates

\left(\dfrac{-3+6}{2},\dfrac{-1+(-3)}{2}\right)=\left(\dfrac{3}{2},-2\right).

Point F is the midpoint of the segment EB, then it has coordinates

\left(\dfrac{\frac{3}{2}+6}{2},\dfrac{-2+(-3)}{2}\right)=\left(\dfrac{15}{4},-\dfrac{5}{2}\right)=(3.75,-2.5).

Let S be the midpoint of segment CB, then it has coordinates

\left(\dfrac{-3+6}{2},\dfrac{-3+(-3)}{2}\right)=\left(\dfrac{3}{2},-3\right).

Point G is the midpoint of segment CS, then its coordinates are

\left(\dfrac{\frac{3}{2}+(-3)}{2},\dfrac{-3+(-3)}{2}\right)=\left(-\dfrac{3}{4},-3\right)=(-0.75,-3).

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3 years ago
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