<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
In order to find what one part is in a ratio, you have to add the ratio up ( 5+ 3) and divide it by the number you're looking for (56). In this case, you get 56/8, which gives you 7. Therefore, each part is worth 7. You then have to multiply both sides of the ratio (5 and 3) by 7. 5x7= 35. 3x7= 21.
Therefore, 56 divided into the ratio of 5:3 is 35:21
Idek how to do that omg but 3 is a triangles sides and wdym by “do”
Answer:
I need help on this thing too someone help
Step-by-step explanation: