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kicyunya [14]
3 years ago
6

Not sure if this is right.

Mathematics
2 answers:
finlep [7]3 years ago
6 0

Answer:

I think your right :)

Step-by-step explanation:

Ber [7]3 years ago
4 0
Yupp your right!!!!!!!!!!
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A rectangle has a length that is increasing at a rate of 10 mm per second with the width being held constant. What is the rate o
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Answer:

the rate of change of the area is Ra= 80 mm² per second

Step-by-step explanation:

the area of a rectangle (A) is

A = L * W , L= length and W= width

if the width remains constant the change in the area is only due to the change in length , thus:

ΔA = Δ( L * W ) = W * ΔL , where ΔA represents the change in area and ΔL represents the change in length

ΔA = W ΔL

denoting Δt as the time required to change, and dividing both sides by Δt

ΔA/Δt = W ΔL/Δt

where Ra=ΔA/Δt = rate of change of the area and RL=ΔL/Δt rate of change of the length.

thus

Ra = W * RL

replacing values

Ra = W * RL = 8 mm * 10 mm/second = 80 mm² /second

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You invested money in two funds. Last year, the first fund paid a dividend of 8% and the second a dividend of 5%, and you receiv
Angelina_Jolie [31]

You invested 11000 in in 2st fund and 9000 in 2nd fund

<h3><u>Solution:</u></h3>

Given that, You invested money in two funds.  

Last year, the first fund paid a dividend of 8% and the second a dividend of 5%, and you received a total of $1330.  

This year, the first fund paid a 12% dividend and the second only 2%, and you received a total of $1500.

Let the amount in Fund I be $x and amount in Fund II be $ y

Then, for last year ⇒ 0.08x+0.05y=1330 ----- eqn (1)  

And for this year ⇒ 0.12x+0.02y=1500 ------- eqn (2)  

Multiply (1) by 2 ⇒ 0.16 x + 0.1 y = 2660  

Multiply (2) by 5 ⇒ 0.6 x + 0.1 y = 7500

Subtract the two equations  

(2) ⇒ 0.6x + 0.1y = 7500

(1) ⇒ 0.16x + 0.1y = 2660

(-) --------------------------------

0.44x + 0 = 4840

x = 11000

Now, from eqn (2)  

0.12(11000) + 0.02y = 1500  

0.02y = 1500 – 1320  

0.02y = 180  

y = 9000

Hence, he invested 11000 in in 2st fund and 9000 in 2nd fund

5 0
3 years ago
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