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4 years ago

1. Opens down, with a stretch of 2, and has zeros at 3 and -2.

Mathematics

1 answer:

Artemon [7]4 years ago

6 0

Answer:

f(x)= -2(x^2-x-6)

Step-by-step

The original formula is f(x)=a(x-h)+k

1) Plug the negative 2 in for a

2) multiply (x-3)(x+2)

3) plug your answer in for 2 in for the parentheses

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Lana71 [14]

Answer:

-7

Step-by-step explanation:

this would mean a = 11 and b = 18, so 11 - 18 = -7

8 0

3 years ago

You invest $10,000 at 7% for one year. What is the interest eamed after one year?

Lana71 [14]

Answer: $11,970

Step-by-step explanation: 10,000 + (1) 7.00% = 11,970

4 0

3 years ago

Help me with b and c pls, i did a

Tresset [83]

B) Minimum= 1
  Q1= 3
  Q3= 8
  Lower Fence= Q1-(IQR*1.5)
= 3-(5*1.5)
= -4.5
Maximum= 11
Median= 7
IQR= 8= 3= 5
Upper Fence= Q3+(IQR*1.5)
= 8+(5*1.5)
= 15.5
c) No. All values are between the lower fence and the upper fence.

6 0

3 years ago

AP Calculus Help Please!

ivanzaharov [21]

4. By the fundamental theorem of calculus,

$\displaystyle\frac{\mathrm dg(x)}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\int_{-2}^xf(t)\,\mathrm dt=f(x)$

$g(x)$ is increasing on those intervals where $g'(x)=\dfrac{\mathrm dg(x)}{\mathrm dx}>0$ . So you have

$g'(x)=f(x)=\begin{cases}3&\text{for }-3\le x$

which is clearly positive for $x\in[-3,0)$ , and in the second interval you have

$-x+3>0\implies x$

Together, this means $g'(x)>0$ for all $x\in[-3,3)$ .

5. When $0\le x\le6$ , $f(x)$ reduces to $-x+3$ , so you have

$g(x)=\displaystyle\int_{-2}^xf(t)\,\mathrm dt=\int_{-2}^03\,\mathrm dt+\int_0^x(-t+3)\,\mathrm dt$
$g(x)=6+\left(3t-\dfrac12t^2\right)\bigg|_{t=0}^{t=x}$
$g(x)=6+3x-\dfrac12x^2$

4 0

4 years ago

What is three x² times nine x⁴

Zolol [24]

Answer:

=27x6

Step-by-step explanation:

=3 × x2 × 9 × x4

=27 × x6

=27x6

7 0

3 years ago