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Licemer1 [7]
3 years ago
8

2p

Mathematics
1 answer:
Lana71 [14]3 years ago
8 0

Answer:

-7

Step-by-step explanation:

this would mean a = 11 and b = 18, so 11 - 18 = -7

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Find g (2w) when g(x) = x^2 - 2x + 1
Ulleksa [173]
G(2w)=(2w)²-2(2w)+1
g(2w)=4w²-4w+1
8 0
4 years ago
HELLLLPPPPPP PLEASEEEEEEEE....
oee [108]
For this case we have the following system of equations:
 5x + 3y = 17
 -8x - 3y = 9
 The solution to this system can be written in matrix form as:
 Ax = b
 Where, A is a matrix that is given by:
 A = [5 3; -8 -3]
 The determinant of this matrix 2 * 2 is given by:
 lAl = (5) * (- 3) - (3) * (- 8)
 lAl = -15 - (-24)
 lAl = -15 + 24
 lAl = 9
 Answer:
 
The determinant for solving this linear system is:
 
lAl = 9
5 0
3 years ago
Read 2 more answers
2x+3<br> 24)2443 = x + 6
Margaret [11]

Answer: I think this is the answer but I got 4877. Just substitute the value of the variable into the equation and simplify.

I hope this helps you and good luck! ☺

3 0
3 years ago
Please help and show work I’m begging
mixas84 [53]
13. Pick a point and see which formula works.
Ay = -4, A'y = 7. Only the formula of selection D makes that translation.

14. Use the compound interest formula A = P*(1 +r/n)^(nt).
..1500*1.015^80 = 4935.99, matching selection C

15. The lid has a perimeter of 90", so the area of the sides is
.. 90" * 24" = 2160 in^2
The area of the lid is
.. 30" * 15" = 450 in^2

The gray area is (2160 -450) in^2 = 1710 in^2 larger, corresponding to selection C.


16. The only formula that maps (7, -1) to (21, -3) is that of selection D.


_____
The middle two problems are the only ones that require you to have prior knowledge. The others could be answered simply by seeing if the answers work.
5 0
4 years ago
Use the definitions of hyperbolic cosine and hyperbolic sine (their formulas) to prove the identity below. Show your work neatly
podryga [215]

Answer:

See below

Step-by-step explanation:

By definition:

\sinh x =  \frac{ {e}^{x}   +   {e}^{ - x} }{2}  \\  \cosh x =  \frac{ {e}^{x}    -    {e}^{ - x} }{2}

We want to show that:

{ \sinh}^{2} x -  { \cosh}^{2}x = 1

We substitute into the left side to get:

( \frac{ {e}^{x}   +   {e}^{ - x} }{2}) ^{2}   - ( \frac{ {e}^{x}    -    {e}^{ - x} }{2}) ^{2}

We apply exponential rule to get:

= \frac{ ({e}^{x}   +   {e}^{ - x})^{2}  }{4}   -  \frac{( {e}^{x}    -    {e}^{ - x} ) ^{2} }{4}

We expand:

= \frac{ {e}^{2x}  + 2 {e}^{ - x}  {e}^{x}  +  {e}^{ - 2x} }{4}  -  \frac{ {e}^{2x}   -  2 {e}^{ - x}  {e}^{x}    +    {e}^{ - 2x} }{4}

= \frac{ {e}^{2x}  + 2  +  {e}^{ - 2x} }{4}  -  \frac{ {e}^{2x}   -  2  +   {e}^{ - 2x} }{4}

= \frac{ {e}^{2x}  + 2  +  {e}^{ - 2x}   - {e}^{2x}    +  2   -  {e}^{ - 2x}}{4}

=  \frac{4}{4} \\  = 1

4 0
4 years ago
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